Q Light Controller+

challange:
if the moving head is far outside the centre, the xy-pad does not map the stage. The corners of the stage do not correspond to the corners of the xy-pad.

feature
It would be very nice to enter pan and tilt to the four corners of the stage and a formula in the background calculates the required pan and tilt to illuminate the point selected on the pad.

bonus
The same formula could be used for the EFX effects so that a circle is the same circle for all moving heads.

solution?
If there is a chance of implementation, I would delve into the necessary maths. The height of the effect above the stage would simplify the calculations.
How about a function which returns the recalculated pan and tilt? A tool could generate the formula which can be assigned to the pad and/or effect?

do we want?

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Have a look overhere: viewtopic.php?p=72777#p72777

your link shows the possibilities that exist. This makes the question more complete. thx.

I am missing the following:
example tilt distances
A=6 m
B= 0 m
C=7.2 m
D= 4 m

the tilt has a minimum of 0 metres and a maximum of 7.2 m. At corner D, the spotlight shines 3.2 m beyond the edge of the stage.

The aim would be to illuminate the corners of the stage at the corners of the pad.

Let rectangle ABCD be
- the XY pad
- the stage
let the moving head be
- 4m above point B
Step 1: PAN for point in degrees
A = 0
B = indifferent
C = 33,69
D = 90

Step 2: Distance to B in metres (edit)
A = 6
B = 0
C = 7,2
D =4

Step 3: Tilt for point in degrees
A = 56,31
B = 90
C = 60,945
D = 45

Example using right-angled triangles
XY Pad at the centre of the stage M (3,2,0):
Pan: 33.69 degrees
Distance: 3.606 metres
Tilt: 42.035 degrees

If you know how high the spotlight is above the stage, the whole thing is quite easy to calculate.


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