Bug on 4.12 in channel fades (dimmer curves)

[hlechevrel]

Hello.
Thank you for the beautiful work of qlcPlus.
Soory for my bad english
I test qlcPlus to use it in theatre
Tested under osx and linux, same problem
When you chnage the dimmer curve (for exemple Linear to Exponential Medium), the highest value dmx change.
For exemple a dimmer is set to value 150 in a scene, and when you execute this scene the value stop at 66.
In Linear mode the value is good (150), what appened ?

TestCurves.qxw

(11.94 KiB) Downloaded 145 times

Hugues

I create a console for working in theatre, if somewone is interested, here is :

08h30v9.qxw

(86.05 KiB) Downloaded 197 times

[kenact]

I did a little testing and found the problem exists with Exponential Deep, Medium, Shallow & Simple, as well as Logarithmic Deep, Medium & Shallow.

At the 150 level set in the example:
Exponential Deep - 32
Exponential Medium - 67
Exponential Shallow - 107
Exponential Simple - 56
Logarithmic Deep - 241
Logarithmic Medium - 217
Logarithmic Shallow - 187


All other curves appear to work properly.


I tested 4.12 on Windows 10 Pro x64


Ken

[kenact]

Another oddity. On the Simple Desk Tab, if you

click on Channel Groups
raise & lower ALL
go to Functions tab
click ALL off
click All Full
go back to Simple Desk (all channels will be in Red)
click the X
all channels go to 150

If you set each channel to a different curve, and follow the steps above, the Exponential, Linear, Logarithmic and Preheat curves work properly, but the Always, Invert & Threshold curves all work like Linear.

[hlechevrel]

-

[hlechevrel]

Thank you Ken for confirmation, I feel less alone. With this procedure, the value on the simple desk is good (150), the curves remains on the good value in the fixtures, but the rise is again linear in execution with the buttons of the virtual console .... To be continued ...

[hlechevrel]

in channel fades (dimmer curves) this function is good with a final value of 100% (dmx255) but bad with another value (under 100%). The curve stopped before the desired value. It's a time calculation problem....